Question

Sulphur dioxide and hydrogen sulphide gasses react in the presence of water as

given bellow.

SO2 + 2H2 S → 2H2 O + 3S. Here hydrogen sulphide is acting as​

Answer 1

Answer:

Here H 2 S is an reducing agent as it is getting oxidized into H 2 O.

Answer 2

Answer

Here 2H2 S is acting as a reducing agent because it is being oxidised into 2H2 O