Question

Sulphur dioxide contains 50% sulphur, hydrogen sulphide contains 5.8% hydrogen and water contains 88.89% oxygen. Which of the following law is explained by the given data?​

Answer 1

Explanation:

us fix

of sulphur (S) as the fixed weight <br> In hydrogen sulphide

<br> Weight of sulphur

<br> Weight of hydrogen

<br>

of sulphur have combined have compound with hydrogen

<br>

sulphur has combined with hydrogen

<br> In sulphur dioxide

<br>

of sulphur have combined with oxygen

<br>

of sulphur has combined with oxygen

<br> Thus, the ratios by weight of hydrogen and oxygen combining with a fixed weight of sulphur in the two compounds is <br> or

(This ratio is not the same) <br> In water

<br> Weight of hydrogen

<br> Weight of oxygen

<br>

<br> Let us compare the ratios (i) and (ii). There are related to each other as : <br>

<br> Since these ratios are the simple whole number multiples of each other, the Law of Reciprocal Proportion is illustrated.