Sulphur exhibits paramagnetism in vapour state why
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The paramagnetism in Sulphur in vapour phase can be explained from the fact that in vapour phase, S 2 is the dominant species and is therefore paramagnetic like O 2, which has two unpaired electrons. So like O 2 molecule, S 2 also has two unpaired electrons in the π*p x and π*p y orbital
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In vapour state sulphur partly exists as S2 molecule and S2 molecule like O2 has two unpaired electrons in the anti bonding , orbital and hence exhibit paramagnetism. Mention the conditions required to maximise the yield of ammonia
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this is because Sulphur is a cycloalkane snd can be made in Ring shape
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