Question

sulphur forms two chlorides s2cl2 and scl2. the equivalent mass of sulphur in scl2 is 16 te equivalent weight of sulphur in s2cl2 is

Answer 1

In the molecule S2Cl2,
2*35.5 g of Chlorine(Cl2) combines with 2*32 g of Sulphur(S)

or, 35.5 g of Cl2 combines with 32 g of S

Therefore, Equivalent weight of Sulphur in S2Cl2(Disulphur dichloride) = 32
Recall : Equivalent weight of an element = parts of which combines with 8 parts of O2 = 1 parts of H = 35.5 parts of Cl2, replace the parts by g(gram)

However for elements with variable valency, variable equivalent weights are possible(using A=E V ). However sulphur exists all in di-,tetra- and octa- atomic forms(having variable atomicity). In that case the question of variable atomic weights will possibly come, creating further chaos. So better to go with the standard form of equivalent weight which I have mentioned:
Equivalent weight of an element = parts of which combines with 8 parts of O2 = 1 parts of H = 35.5 parts of Cl2, replace the parts by g(gram)

Answer 2

Answer:

Explanation:

In the molecule S2Cl2, 2*35.5 g of Chlorine(Cl2) combines with 2*32 g of Sulphur(S) or, 35.5 g of Cl2 combines with 32 g of S Therefore, Equivalent weight of Sulphur in S2Cl2(Disulphur dichloride) = 32 Recall : Equivalent weight of an element = parts of which combines with 8 parts of O2 = 1 parts of H = 35.5 parts of Cl2, replace the parts by g(gram) However for elements with variable valency, variable equivalent weights are possible(using A=E V ). However sulphur exists all in di-,tetra- and octa- atomic forms(having variable atomicity). In that case the question of variable atomic weights will possibly come, creating further chaos. So better to go with the standard form of equivalent weight which I have mentioned: Equivalent weight of an element = parts of which combines with 8 parts of O2 = 1 parts of H = 35.5 parts of Cl2, replace the parts by g(gram)

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