Sulphur in vapour state exhibits paramagnetism explain
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In vapour state sulphur partly exists as S2 molecule and S2molecule like O2 has two unpaired electrons in the anti bonding , orbital and henceexhibit paramagnetism. ... It donates its electron pair and forms a linkage with metal ion.
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hey here is your answer..
In vapour state, Sulphur partly exists as S2molecule, which has two unpaired electrons in antibinding pie orbitals, just like the O2molecule. Hence, it exhibits paramagnetism. Because in vapour state it exists as S2 molecule and has 2 unpaired electrons in antibonding pi orbital and hence exhibit paramagnetism.
In vapour state, Sulphur partly exists as S2molecule, which has two unpaired electrons in antibinding pie orbitals, just like the O2molecule. Hence, it exhibits paramagnetism. Because in vapour state it exists as S2 molecule and has 2 unpaired electrons in antibonding pi orbital and hence exhibit paramagnetism.
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