Sulphur reacts with potassium superoxide
(KO2) as 2KO2 + S==== K2SO4
How many moles of K2SO4 will be formed when 1 mole of each KO2 and S is reacted?
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Given:
The reaction between Sulphur and Potassium Superoxide.
No of moles of Sulphur = 1
No of moles of Potassium Superoxide = 1
To Find:
The no of moles of K2SO4 formed from the given amount of Sulphur and Potassium Superoxide.
Calculation:
- The given reaction is:
2 KO2 + S → K2SO4
- According to the given reaction:
2 moles of KO2 react with 1 mole of S to produce 1 mole of K2SO4.
⇒ 1 mole of KO2 will react with 0.5 moles of S to produce 0.5 moles of K2SO4.
- Here, KO2 will act as a limiting reagent as it gets used up completely and 0.5 moles of S will be left unreacted.
- So, 0.5 moles of K2SO4 is formed when 1 mole of each KO2 and S is reacted.
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2
Answer:
0.5 moles
Explanation:
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