Question

sulphur trioxide is prepared by the following two reactions :

S8(s) + 8O2(g) --> 8SO2(g)
2SO2(g) + O2(g) --> 2SO3(g)

How Many grams of SO3 are produced from one mole of S8?

Answer 1

Given reactions :

S₈ +       8O₂ ---->  8SO₂
1mol                      8mol

2SO₂  + O2₂---->  2SO₃ 
 2mol                     2mol
∴8mol   -------->     8mol

Therefore, Wt of So3=number of moles x Molecular weight                                                                          =8x[32+3x16]
                                    =8x80
                                    =640g
∴640g  of SO3 are produced from one mole of S8

Answer 2

Answer:

640 gram of SO3 are produced from 1 mole of S8...

Explanation:

S₈ +       8O₂ ---->  8SO₂

1mol                      8mol

2SO₂  + O2₂---->  2SO₃ 

 2mol                     2mol

∴8mol   -------->     8mol

Therefore, Weight of SO3=number of moles x Molecular weight                                                                          =8x[32+3x16]

                                   =8x80

                                   =640g

Good Question