sum=(1+2) /(1*2) +(2+3) /(2*3) +(3+4) /(3*4)..... n terms
Write a JAVA program to print the above series.
ANSWER ONLY IF YOU KNOW
Answers
Answered by
6
Answer:
=
=
x^2-y^2=(x+y)(x-y)
==
x^2-y^2=(x+y)(x-y)
(x)=(sin(x)+cos(x))(sin(x)−cos(x))
=(\sin (x)+\cos (x))(\sin (x)-\cos (x))=(sin(x)+cos(x))(sin(x)−cos(x))
=
x^2-y^2=(x+y)(x-y)
=
==
Similar questions