Question

Sum 1,√3​,3,.... to 12 terms.​

Answer 1

Answer:

Its a GP series with

First term, a = 1

Common ratio, r = √3

Number of terms, n = 12.

Sum is given by

$\frac{a( {r}^{n} - 1) }{r - 1} \\ = \frac{1( ({ \sqrt{3} )}^{12} - 1 )}{ \sqrt{3} - 1} \\ = \frac{729 - 1}{ \sqrt{3} - 1} \\ = \frac{728}{ \sqrt{3} - 1 }$

Answer 2

Answer:

this is correct..............................