Question

sum 3 consecutive natural numbers is 123 find the numbers

Answer 1

n+(n+1)+(n+2)=123
3n+3=123
3n=123-3
3n=120
n=40
n+1=41
n+2=42
therefore the numbers are 40,41,42

Answer 2

Let the numbers be X,X+1,X+2

Therefore X+1+X+2+X+3=123

or 3x+6=123

or 3x=117

or X= 117/3

X=39

So the numbers are 39,40,41