Question

sum and product of zeroes are 5,6 then quadratic polynomial​

Answer 1

___________________

$\mathcal\violet{quadratic\:polynomial\:is written\:in\:the\:form\:of:-}$

• $x^{2} - (\alpha+\beta)x + (\alpha\beta)$

_________________

$\mathbb\red{\underline{Answer:-}}$

= $x^{2} - ( 5 + 6 ) + ( 5 × 6 )$

= $x^{2} - 11 + 30$

• Hence , your answer :-

$x^{2} - 11 + 30$

Answer 2

Answer:

The polynimial can be k(x^2-5x+6)

here, k can be any real number u prefer

example, when k = 1, tge equation us x^2-5x+6

Step-by-step explanation:

quadratic polynomial = k[x^2 -(sum of zeroes) *x +(product of zeroes)] where k is any real number

here, sum of zeroes = 5 and product of zeroes = 6

therefore, by substituting values we get:-

k(x^2-5x+6) where k is any real number

Thank you for your attrntion

Kindly mark this answer as brainlist if it helps you