sum no 11 plz help me
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Construction: drop a perpendicular from O on the AD at some pt. M
we know that a line drawn perpendicular from the center to a chord bisects the chord.
therefore BM = FM = 4 ------(1)
Consider the bigger circle, since the center is same and OM is also perpendicular to AD,
AM = MD = 6-------(2)
subtract (1) from (2)
AM - BM = DM - FD = 6 - 4
AB = CD = 2 -----(3)
AC = AB+ BC = 2 + 8 = 10
similarly, BD = 8+2 = 10 ;)
we know that a line drawn perpendicular from the center to a chord bisects the chord.
therefore BM = FM = 4 ------(1)
Consider the bigger circle, since the center is same and OM is also perpendicular to AD,
AM = MD = 6-------(2)
subtract (1) from (2)
AM - BM = DM - FD = 6 - 4
AB = CD = 2 -----(3)
AC = AB+ BC = 2 + 8 = 10
similarly, BD = 8+2 = 10 ;)
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