Sum of 1-100th term in AP
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AP = 1 , 2 , 3 , 4........., 100
Here,
First term ( a ) = 1
Common difference ( d ) = 2 - 1 = 1
Last term ( Tn ) = 100
a + ( n - 1 ) × d = 100
1 + ( n - 1 ) × 1 = 100
1 + n - 1 = 100
n = 100
Number of terms = 100
Sn = n/2 × [ 2a + ( n - 1 ) × d ]
S100 = 100/2 × [ 2 × 1 + ( 100 - 1 ) × 1 ]
=> 50 ( 2 + 99 )
=> 50 × 101
=> 5050
Hence,
Sum of the terms of the given AP Will be equal to 5050.
Here,
First term ( a ) = 1
Common difference ( d ) = 2 - 1 = 1
Last term ( Tn ) = 100
a + ( n - 1 ) × d = 100
1 + ( n - 1 ) × 1 = 100
1 + n - 1 = 100
n = 100
Number of terms = 100
Sn = n/2 × [ 2a + ( n - 1 ) × d ]
S100 = 100/2 × [ 2 × 1 + ( 100 - 1 ) × 1 ]
=> 50 ( 2 + 99 )
=> 50 × 101
=> 5050
Hence,
Sum of the terms of the given AP Will be equal to 5050.
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