Question

sum of (1/7)th of the smaller and(1/3)rd of the larger number of the consecutive odd numbers is 24.Find out the numbers​

Answer 1

Answer:

Integers are 49 and 51

Step-by-step explanation:

Let the smaller odd integer be x and larger odd integer be x +2

According to the given condition:

X/7 + (X+2)/3= 24

Finding LCM we get

3x/21 + (7x+14) /21 =24

(10x + 14)/21= 24

10x + 14 = 21 *24

10x = 504-14

x = 490/10 = 49

Therefore smaller integer is 49 and larger is 51

Answer 2

Answer:

Integers are 49 and 51

Explanation:-

Let the smaller integer be x and larger odd integer be x +2

According to the given condition:

X/7+(X+2)/3=24

Finally LCM we get=>

3x/21+(7x+14)/21=24

(10x+14)/21=24

10x+14=21*24

10x=504-14

x=490/10=49

Therefore smaller integer is 49 and larger is 51.....

Hope it helps!✌️

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