sum of 1 to n natural number is 36,then the find the value of n
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36=n/2(2×1+(n-1)×1)
72=n(2+n-1)
72=n^2+n
n^2+n-72
n^2+9n-8n-72
n(n+9)-8(n+7)
(n+9)(n-8)
n=-9(neglecting because it can't be -ve)
n=8 Ans
72=n(2+n-1)
72=n^2+n
n^2+n-72
n^2+9n-8n-72
n(n+9)-8(n+7)
(n+9)(n-8)
n=-9(neglecting because it can't be -ve)
n=8 Ans
samra5:
wrog answer
wrong
but it is wrong
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