Math, asked by siddhukr9913, 11 months ago

Sum of 10 natural numbers in assembly language in arm

Answers

Answered by tanaya27

1

Answer:

sum of Frist 10 natural numbers is 55.

Step-by-step explanation:

sum of Frist 10 natural numbers is= n(n+1)/2

=10(11)/2

= 110/2

= 55

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