Sum of 10th and 70 th terms of an arithmetic sequence is 806. If its 20 th term is 203 ,find its 60 th term ?
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Answer:
Step-by-step explanation:
a₁₀ + a₇₀ = 806
a + 9 d + a + 69 d = 806
=> 2 a + 78 d = 806
=> a + 39 d = 403
also given that a₂₀ = 203
=> a + 19 d = 203
20 d = 200
=> d = 10 a = 13
60th term = a + 59 d
13 + 59×10
=> 13 + 590
=> 603
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