sum of 11a³-3b² and 4a³+6b²
Answers
Answered by
1
Answer:
15a³ + 3b²
Step-by-step explanation:
11a³-3b² + 4a³+6b²
=> [(11+4)a³] + [(-3+6)b²]
=> 15a³ + 3b²
Answered by
0
Answer:
3 (5a upon 3 - 3b upon 2)
Step-by-step explanation:
11a upon 3 - 3b upon 2 + 4a upon 3 + 6b upon 2
= 15a upon 3 - 9b upon 2
= 3 ( 5a upon 3 - 3b upon 2 )
Hope it will help :)
Similar questions
Social Sciences,
1 month ago
Science,
3 months ago
Social Sciences,
3 months ago
English,
9 months ago
Chemistry,
9 months ago
Math,
9 months ago