Math, asked by diyaerram, 3 months ago

sum of 11a³-3b² and 4a³+6b²​

Answers

Answered by dfvdfdbfdbfdfdg
1

Answer:

15a³ + 3b²

Step-by-step explanation:

11a³-3b² + 4a³+6b²​

=> [(11+4)a³] + [(-3+6)b²​]

=> 15a³ + 3b²

Answered by jaderuby523
0

Answer:

3 (5a upon 3 - 3b upon 2)

Step-by-step explanation:

11a upon 3 - 3b upon 2 + 4a upon 3 + 6b upon 2

= 15a upon 3 - 9b upon 2

= 3 ( 5a upon 3 - 3b upon 2 )

Hope it will help :)

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