Question

Sum of 15th & 16th term of an arithmetic sequence is 125. What is the sum of its 7th & 24th term.

b. Find the sum of the first 30 terms of the above arithmetic sequence.

C. 18th term of an arithmetic sequence is 35. Find sum of its first 35 terms?

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Answer 1

Step-by-step explanation:

Explanation:

Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.

The sum of the first three terms is (x−d)+x+(x+d)=111.

x+x+x+d−d=3x=111

x=1113=37

Now we know that the second term is 37. The fourth term is the second term plus twice the common difference: x+2d. Since the second and fourth terms are 37 and 49, respectively, we can solve for the common difference.

x+2d=37+2d=49

2d=12

d=6

The common difference is 6. The first term is x−d=37−6=31.

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Answer 2

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