Question

sum of 18 consecutive natural numbers is a perfect square the smallest possible value of this sum is

Answer 1

I think it's ur answer .....
I m not sure whether it is right or wrong ........
pls comment me about my answer

Answer 2

Answer:225

Step-by-step explanation:

Sn=(n/2)(2a+(n-1)d)

=> S18=18/2(2a+(18-1)d)

=9(2a+17d)

If consecutive natural numbers then value of d=1

S18=9(2a+17)

Here minimum value of a=4 to make (2a+17) a perfect square

S18=9(2*4+17) =9(8+17) =9*25

S18=225