sum of 1st 100 odd numbers =
pls... help me frnds
pls... say correct answers
Answers
Answer:
sum of first 100 odd numbers = 10000
Step-by-step explanation:
sum of 1st 100 odd numbers = 1 + 3 + 5 + ... 100terms
1,3,5,.. is an Arithmetic progression, with
a= 1
d = 3-1 = 2
we know, Sₙ = (n/2)[2a+(n-1)d]
=> S₁₀₀ = (100/2) [ 2(1) + (100-1)2 ]
=> S₁₀₀ = 50 [ 2 + (99)2 ]
=> S₁₀₀ = 50 [ 2 + 198 ]
=> S₁₀₀ = 50 [ 200 ]
=> S₁₀₀ = 10000
another method,
sum of first n odd numbers = n²
so, sum of first 100 odd numbers = 100²
= 10000
Answer:
n = 100
Let a1 = 1, a2 = 3
a2 - a1 = d
3 - 1 = 2
So, d = 2
General term, aN = a + (n - 1)d
aN = 1 + (100-1)2
= 1 + 99 × 2
= 1 + 198 = 199
Sn = n/2 (a1 + a2)
= 100/2 (1 + 199)
= 50 × 200
= 10000
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