Math, asked by btr59310gmailcom, 6 hours ago

sum of 1st 15 terms of an arithmetic sequence is 525 its 12th term is 51 (a) find its 8th term (b) find the 1st term ​

Answers

Answered by Athul4152
0

 \bf\huge\underline{\underline{ Given :- }}

  • sum of 1st 15 terms of an AP is 525
  • 12th term is 51

 \bf\huge\underline{\underline{ To \: Find:- }}

  • 8th term
  • 1st term

 \bf\huge\underline{\underline{ Formula \: Used }}

  •  \boxed{\bf middle \:  term =  \frac{sum}{ no. \: of \: terms }}  \\

  •  \boxed{\bf d = \frac{ x_{n} - x_{m}  }{n- m}  } \\

 \bf\huge\underline{\underline{ Answer :- }}

 \bf\large\underline{\underline{ 8^{th} term  }}

  •  \boxed{\bf middle \:  term =  \frac{sum}{ no. \: of \: terms }}  \\

  •  x_{8} = \frac{525}{15}   \\

  • x_{8}= 35

 \rule{15cm}{0.02cm}

8th term = 35

 \rule{15cm}{0.02cm}

 \bf\large\underline{\underline{ 1^{st} term  }}

  •  \boxed{\bf d = \frac{ x_{n} - x_{m}  }{n- m}  } \\

  • common difference =  \bf d = \frac{51 - 35}{12 - 8 }   \\

  • common difference =  \bf \frac{16}{4} \\

  • common difference =  \bf 4

  • \bf x_{8} = 35

  • \bf x _{1} = 35 - 7d

  •  \bf x_ {1 } = 35 - 28

  •  \bf x_ {1 } = 7

 \rule{15cm}{0.02cm}

1st term = 7

 \rule{15cm}{0.02cm}

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