Sum of 1st 3 terms is an ap is 24 and sum of their squares is 224 find first 3 terms of ap
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Answer:therefore the three terms are,
a-d = 8-4=4
a=8
a+d=8+4=12
Step-by-step explanation:
let the terms be a-d, a, a+d
sum=24
a-d+a+a+d=3a=24
a=8
(a-d) ^2+a^2+(a+d)^2=224
a^2+2(a^2+d^2)=224
3a^2+2d^2=224
3(64)+2d^2=224
2d^2=224-192
d^2=32/2
d=√16=4 put in numbers(assumed)
therefore the three terms are,
a-d = 8-4=4
a=8
a+d=8+4=12
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