sum of 1st and 21st term of an arithmetic sequence is 140
what is its 11th term
write the sequence of first term is 10
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Step-by-step explanation:
nth term tn=a+(n−1)d
a= First term
d= Common difference
n= number of terms
tn=nth term
Given
T5+T9=30
a+4d+a+8d=30
2a+12d=30
a+6d=15
a=−6d+15
now
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