Question

Sum of 1st three of an A.P is 15 and product 1st and 3rd terms exceeds by second term by 16 .Find the terms of an A.P

Answer 1

I don't know sorry I can don't

Answer 2

Hey.. I think this can be ur answer!!

S3=15
3/2(2a+2d)=15
2a+2d=10
a+d=5
d=5-a - (1)

Now,
T1*T3=16+T2
a(a+2d) =16+a+d,
a2+ 2ad = 16 +5
a2+2ad=21
a2+2a(5-a)=21
a2+10a-2a2=21
a2-10a+21=0
a2-3a-7a+21=0
a(a-3)-7(a-3)
a=3 or a=7
d=5-a
d=5-3=2 or d=5-7=-2


Hope it helps you dear ☺️☺️