Question

Sum of 2 angles of a triangle is 80° and difference is 20° . Find the angles

Answer 1

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Let a , b and c be the angles of a triangle.

Given that, a + b = 80° ---------1)

a - b = 20°-----------2)

Now adding equation 1) and 2) we get :-

( a + b ) + ( a - b ) = 80 + 20

=) 2a=100

=) a=50°

So, b=80 - 50 =30

So, b= 30°

=) c = 180 - ( 50+30) =180 - 80 =100

So, c = 100°

Hence, angles of a triangle are 50° , 30° and 100°.




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Hope it helps

Answer 2

let us take a angle as x and another be y
x+y=80
x-y=20
so x+y+x-y=80+20
so x+y+x-y=100
2x=100
x=50
first angle is 50degree
x+y=80
so y=80-50
second angle is 30 degree
let third be a
then a+50+30=180
a=180-80
third angle is 90 degree