sum of 2 consecutive numbers multiples of 184
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Consecutive multiples of any number is represented as
n A,
where n is any Natural number and A be the mentioned number.
Here, the number is 184
We can take the multiples as (n × 184), where n is any Natural number.
We take n = 1, 2, 3, 4, ...
When, n = 1, the first multiple of 184 is
(1 × 184) = 184
When n = 2, the second multiple of 184 is
(2 × 184) = 368
Hence, 184 and 368 are two consecutive multiples of 184
Therefore, the required sum is
= 184 + 368
= 552
#MarkAsBrainliest
Consecutive multiples of any number is represented as
n A,
where n is any Natural number and A be the mentioned number.
Here, the number is 184
We can take the multiples as (n × 184), where n is any Natural number.
We take n = 1, 2, 3, 4, ...
When, n = 1, the first multiple of 184 is
(1 × 184) = 184
When n = 2, the second multiple of 184 is
(2 × 184) = 368
Hence, 184 and 368 are two consecutive multiples of 184
Therefore, the required sum is
= 184 + 368
= 552
#MarkAsBrainliest
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