Question

sum of 2 consicutive integers is 21.the smallest of these number is?​

Answer 1

Answer:

Answer will be 11...

hope it will help you!

Answer 2

Answer:

let the first no be =x

the consecutive no be =x+1

A/Q

X+X+1=21

2X=21-1

2X=20

X=10

FIRST NO BE X=10

2ND NO BE X+1=10+1=11

Step-by-step explanation:

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