sum of 2 digit no. is 9 when we interchange it is found new no. is greater by 27 from original no. find the no.
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Answered by
1
the orginal no. is 36
let the tens place be x
let the once place be y
so,10x + y = 9
now by interchanging we get
10y + x = 27 + (10x + y)
9y + 9x = 36
so the answer is 36
let the tens place be x
let the once place be y
so,10x + y = 9
now by interchanging we get
10y + x = 27 + (10x + y)
9y + 9x = 36
so the answer is 36
Anonymous:
can it be 18
no
because if we interchange the no. the differencr is 63 as per the question it should be only 27
please mark as brainliest
Answered by
0
let the tens place be 10x and units place be y
sum x+y=9...(1)
interchange. 10y+x=27+(10x+y)
10y-y+x-10x=27
9y-9x=27
divide by 9
y-x=3.....(2)
solve 1 and 2
2y=12
y=6
put y=6 in 1
x+6=9
x=3
the no.is 36
hope it helps
sum x+y=9...(1)
interchange. 10y+x=27+(10x+y)
10y-y+x-10x=27
9y-9x=27
divide by 9
y-x=3.....(2)
solve 1 and 2
2y=12
y=6
put y=6 in 1
x+6=9
x=3
the no.is 36
hope it helps
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