Question

sum of 2 digit number and number obtained by reversing the order of the digit is 121if one digit is 3 more than the other find the number​

Answer 1

Answer:

Step-by-step explanation:

let unit digit be x and tens digit be x+3

original number=10(x+3)+x

new number obtained by  reversing the order of original number=10x+(x+3)

A.T.S

10(x+3)+x+10x+(x+3)=12

10x+30+x+10x+x+3=12

22x+33=12

22x=12-33

22x=-21

x=- 21/22