Sum of 2 digit number is 9 if we interchange the digits the resultant number is greater by 27
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Let x be ten's digit and y be the unit digit.
According to first condition :
x+y =9. -(I)
According to second condition :
10y+x=10x+y+27
10y-y+x-10x=27
9y-9x=27
9(y-x)=27
Y-x=3. -(ii)
Add (I) and (ii)
X+y=9
-x+y=3
2y=12
Y=6
Hence;x=9-y
X=9-6
X=3
Hence,required number is 10x+y
which is equal to 10(3)+6
i.e 36
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