Question

sum of 2 digits.numbers and the number oftend by reversing its digits is 66.if the different of both digits is 2.then find the numbers.

Answer 1

A B  + BA = 66
AB = 10 * A + B 
B A =  10 * B  + A
So AB + BA = 11 A + 11 B = 11 (A+B)  =  66
A + B = 6
A = B + 2  =>  B + 2 + B = 6  => B = 2        => A = 4
numbers are    24 and 42

Answer 2

let x and y be two digits   hence tens digit numbr will be 10x+y
on reversing it will be 10y+x
a/q  10x+y+10y+x=66   or   x+y=11
also x-y=2  
adding both eq. we get x=13/2  y=9/2