Sum of 24 terms of progression 3,10, 21, 36, 55,
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s=24/2[2*3+(24-1)7]
s=12[6+23*7]
s=12[6+161]
s=12*167
s=2004
therefore the sum of 24th term is 2004
s=12[6+23*7]
s=12[6+161]
s=12*167
s=2004
therefore the sum of 24th term is 2004
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