sum of 2digit is 8when you add 18 the digits get reversed.find the number
Answers
Answered by
1
➡HERE IS YOUR ANSWER⬇
Let, the digits are a and b.
Then the number be (10a + b).
When the digits are reversed, the number is (10b + a).
Given that :
a + b = 8 .....(i)
and
(10a + b) + 18 = 10b + a
or, 9a - 9b + 18 = 0
or, a - b = -2 = 0 .....(ii)
Adding (i) and (ii), we get
2a = 6
i.e., a = 3
So, b = 5
Hence, the number is 35.
⬆HOPE THIS HELPS YOU⬅
Let, the digits are a and b.
Then the number be (10a + b).
When the digits are reversed, the number is (10b + a).
Given that :
a + b = 8 .....(i)
and
(10a + b) + 18 = 10b + a
or, 9a - 9b + 18 = 0
or, a - b = -2 = 0 .....(ii)
Adding (i) and (ii), we get
2a = 6
i.e., a = 3
So, b = 5
Hence, the number is 35.
⬆HOPE THIS HELPS YOU⬅
Answered by
0
please mark me brainiliest. ....please bro
Attachments:
Similar questions