Question

Sum of 2nd & 5th term is 10. Sum of 6th & 10th term is 64 ,then find the value of a . *​

Answer 1

Step-by-step explanation:

Slove eq1 and 2nd by elimination method..

And you will get your answer

Answer 2

Answer:

Given : a2 + a5 = 10

(a+d) + (a+4d) = 10

2a + 5d = 10 ............................(1)

a6 + a10 = 64

(a+5d) + (a+9d) = 64

2a + 14d = 64 ............................(2)

Subtract equation (1) from (2)

2a + 14d = 64 ............................(2)

2a + 5d = 10 ............................(1)

- - -

9d = 54

d = 54/9

d = 6

Substitute d=6 in equation (1)

2a + 4d = 10

2a +4(6) = 10

2a = 10-24

a = -14/2

a = -7

I hope you satisfied with my ANSWER.

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