Sum of 2nd and 3rd terms of a G.P. is 3 and sum of next two is 12 ; find the first term.
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So you have that
ar+ar2=12ar2+ar3=60
Then
a=12r+r2ar2+ar3=60
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a=12r+r212r+r2r2+12r+r2r3=60
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12r+r2r2+12r+r2r3=6012r+r2r+r212
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12r2+12r3=60(r+r2)
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12r3−48r2−60r=0
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12r2−48r−60=0
$ Now solve this equation and you will find 2 solutions. Then you should verify which one satisfies the first equation
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