sum of 3 consecutive multiple of 7 is 63. Find these multiple
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Answered by
6
Answer:
Let the three multiples be 7x,7x+7 and 7x+14.
According to the question,
7x+7x+7+7x+14=63
21x+21=63
21x=63−21
x= 42/21
x=2
So,
7x=14
7x+7=21
7x+14=28
Hence, this is the answer.
Answered by
0
Answer:
Thus, the three consecutive multiples of 7 are: 14, 21 and 28
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