Question

Sum of 3 consecutive multiples of 11 is 363.find the numbers

Answer 1

Answer:

let the three consecutive multiples of 11 be x.,x+11,x+22

a/q

x+x+11+x+22=363

3x+33=363

3x= 363-33

3x=330

x=110

1st no= x=110

2nd no=x+11=110+11=121

3rd no = x+22=110+22=132.

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Answer 2

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.