sum of 3 consecutive multiples of 11 is 363. find the numbers
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11x+(x+1)11+(x+2)11=363
11x+11x+11x+11+22=363
33x+33=363
x+1=363÷33
x+1=11
x=10
hence the numbers are 110;121;132
11x+11x+11x+11+22=363
33x+33=363
x+1=363÷33
x+1=11
x=10
hence the numbers are 110;121;132
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