sum of 3 consecutive multiples of 12 is 324. find the multiples
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Answer:
96, 108, 120
Step-by-step explanation:
Let the three consecutive multiples of 12 be x, x+12, x+24
As per the data,
sum of consecutive multiples= 324
(x)+(x+12)+(x+24) =324
3x+36=324
3x=324-36
3x=288
x=288/3
x=96
Therefore, the multiples are x=96 , x+12= 108 ,x+24=120
The three multiples are 96,108,120
Hope it helps u...
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