Question

sum of 3 consecutive multiples of 8 is 888 find the multiples

Answer 1

Let the first multiple of 8 be 8x.

Therefore the second consecutive multiple of 8 will be 8(x+1)

Also the third consecutive multiple of 8 will be 8(x+2).

It is given that the sum of these three consecutive multiples of 8 is 888

=> 8x + 8(x+1) + 8(x+2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

Take 24 on the RHS

=> 24x = 888 - 24

=> x = 864/24

=> x = 36.

Therefore First multiple of 8 be 8x = 8 x 36 = 288

Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296

Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304

If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

Answer 2

Let the three consecutive multiples be 8x, 8x+8,8x+16

If there sum is 888

8x+8x+8+8x+16=888

24x+24=888

24(x+1)=888

x+1=888/24

x=37-1

x=36

Then the multiples are 8*36=288

(8*36)+8=296

(8*36)+16=304