Question

Sum of 3 consecutive natural numbers is 33. What are the numbers?​

Answer 1

$let \: three \: consecutive \: \\ numbers \: be \\ \\ = \: x, \: x + 1 \: \: and \: \: x + 2$

$x + x + 1 + x + 2 = 33 \\ \\ x + x + x + 2 + 1 = 33 \\ \\ 3x + 3 = 33 \\ \\ 3 x = 33 - 3 \\ \\ 3x = 30 \\ \\ x = \frac{30}{3} \\ \\ x = 10$

$The \: numbers \: are \\ \\ x + 1 = 10 + 1 = 11 \\ \\ x + 2 = 10 + 2 = 12$

$The \: numbers \: are \: \\ \\ = 10 ,11 \: and \: 12$

Answer 2

Question:-

Sum of 3 consecutive natural numbers is 33. What are the numbers?

Answer:-

The numbers are 10 , 11 and 12.

Explanation:-

Let three consecutive numbers be :-

$= x , \: x + 1 \: and \: x + 2$

$x + x + 1 + x + 2 = 33$

$x + x + x + 2 + 2 = 33$

$3x + 3 = 33$

$3x = 33 - 3$

$3x = 30$

$x = \frac{30}{3}$

$x = 10$

•°• The numbers are :-

$x = 10$

$x + 1 = 10 + 1 = 11$

$x + 2 = 10 + 2 = 12$