Question

sum of 3 consecutive numbers is 144.Find the number (show meathod​

Answer 1

$\huge\mathbb{SOLUTION:-}$

Let the number be x

And this is consecutive number then

1st Number=x

2n Number=x+1

3rd Number=x+2

• Now given that the sum of these numbers is 144
• So :-

$\bf\underline{\red{According\:To\: Question:-}}$

$\sf\implies x+(x+1)+(x+2)=144\\ \\ \sf\implies 3x+3=144\\ \\ \sf\implies 3x=144-3\\ \\ \sf\implies 3x=141\\ \\ \sf\implies x=\cancel{\frac{141}{3}}=47\\ \\ \sf\implies x=47$

• The value of x is 47

• 1st number is 47

• 2nd is 47+1 =48

• And 3rd=47+2= 49

$\boxed{\sf{3\: consecutive\:Numbers}={\mathfrak{47,\:48,\:49}}}$

Answer 2

$\huge {\boxed{\purple{SOLUTION:}}}$

Let

• First number = x
• Second number = x+1
• Third number = x+2

It is given that the sum of the three consecutive numbers is 144.

Atq,

$\implies x + (x + 1) +( x + 2) = 144\\ \implies x + x + 1 + x + 2= 144\\ \implies 3x + 3 = 144 \\ \implies 3x = 144 - 3 \\ \implies 3x = 141 \\\implies x = \frac{141}{3} \\ \implies x = 47$

Hence,

• First number = 47
• Second number = 47+1=48
• Third number = 47+2=49