sum of 3 consecutive numbers is 63 then find the product of extremes
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Heya Buddy
Let the consecutive numbers be (x-1) , x , (x+1)
Sum = 63
3x= 63
-->x=21
Hence ,the no.s are 20, 21 ,22
Product of the two extremes = 20*22
--------> 440 is your answer ^_^
Tell me if any doubt is there
Let the consecutive numbers be (x-1) , x , (x+1)
Sum = 63
3x= 63
-->x=21
Hence ,the no.s are 20, 21 ,22
Product of the two extremes = 20*22
--------> 440 is your answer ^_^
Tell me if any doubt is there
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