sum of 3 consecutive odd number is 33. what is the number?
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Answered by
17
Let the three consecutive numbers be x + 1, x + 3 and x + 5
A/Q,
x + 1 + x + 3 + x + 5 = 33
3x + 9 = 33
3x = 33 - 9
3x = 24
x =
x = 8
x + 1 = 8 + 1 = 9
x + 3 = 8 + 3 = 11
x + 5 = 8 + 5 = 13
The numbers are 9, 11 and 13
A/Q,
x + 1 + x + 3 + x + 5 = 33
3x + 9 = 33
3x = 33 - 9
3x = 24
x =
x = 8
x + 1 = 8 + 1 = 9
x + 3 = 8 + 3 = 11
x + 5 = 8 + 5 = 13
The numbers are 9, 11 and 13
KeerthhanaRajK:
Hi friend
Answered by
3
Let the three consecutive numbers be x + 1, x + 3 and x + 5
A/Q,
x + 1 + x + 3 + x + 5 = 33
3x + 9 = 33
3x = 33 - 9
3x = 24
x = \frac{24}{3}324
x = 8
x + 1 = 8 + 1 = 9
x + 3 = 8 + 3 = 11
x + 5 = 8 + 5 = 13
\therefore{}∴ The numbers are 9, 11 and 13
A/Q,
x + 1 + x + 3 + x + 5 = 33
3x + 9 = 33
3x = 33 - 9
3x = 24
x = \frac{24}{3}324
x = 8
x + 1 = 8 + 1 = 9
x + 3 = 8 + 3 = 11
x + 5 = 8 + 5 = 13
\therefore{}∴ The numbers are 9, 11 and 13
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