Sum of 3 consecutive odd number is 63
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2
Let 3 consecutive odd numbers be 2x+1,2x+3 and 2x+5.
Then according to the given conditions,
(2x+1)+(2x+3)+(2x+5)=63
6x+9=63
6x=54
x=54/6
x=9
2x+1=19
2x+3=21
2x+5=23
Thus the three consecutive odd numbers are 19,21 & 23.
Then according to the given conditions,
(2x+1)+(2x+3)+(2x+5)=63
6x+9=63
6x=54
x=54/6
x=9
2x+1=19
2x+3=21
2x+5=23
Thus the three consecutive odd numbers are 19,21 & 23.
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Answered by
0
Answer:
19, 21 and 23
Step-by-step explanation:
We know that consecutive odd number differ by 2 so,
Let the three consecutive odd numbers be x, ( x + 2 ) and ( x + 4 ) respectively.
We can derive the following equation by reading the question carefully,
x + ( x + 2 ) + ( x + 4 ) = 63
x + x + 2 + x + 4 = 63
3x + 6 = 63
3x = 63 - 6
3x = 57
x = 57 / 3
x = 19
Therefore we can calculate the consecutive odd numbers now:
First Consecutive Odd Number = 19
Second Consecutive Odd Number = 19 + 2 = 21
Third Consecutive Odd Number = 19 + 4 = 23
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