Question

 sum of 3 consicitive integer is 216. find the middle integer.                                     

Answer 1

let the consecutive numbers be  a , a+1 , a+2
Their sum = a+ a+1+a+2  = 3a + 3 
so  3a+3 = 216  => 3a = 213  =>  a = 71
numbers are 71, 72, 73

Answer 2

let the first no be a..
so the rest of the nos are.a+1 and a+2.
  a+a+1+a+2=216
 or 3a+3=216
or 3a=213
  a=71.
so the nos are 71,72,73