Question

Sum of 3 positive integers is 6. If these 3 positive integers are respectively a, b and c. All three are in increasing order respectively. Then how many possible combinations are there.

Answer 1

Answer:

Solution:-

$..$

→ Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.

720 possible combinations.

_______________________________

Hope it helps you dear!

Answer 2

$\huge\tt\colorbox{pink}{Answer}$

_________________________

Solution:-

→ Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.

720 possible combinations.

________________________