Question

sum of 3 terms of an AP is 12 and sum of square of the term is 56 find the term

Answer 1

Terms are (a-d), a, (a+d)

Now,

a-d+a+a+d = 12

3a = 12

a= 12/3

a =4
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(a-d)² +a² +(a+d)² = 56

a² + d² -2ad + a² + a² + d² +2ad = 56

Putting the value of a, -2ad and 2ad will cancel

4² +d² +4² +4² +d² = 56

16+16+16 +2d²=56

2d² =56-48

2d² = 8

d² =8/2

d² =4

d=√4

d= 2


Now,

Terms are :-

a, (a-d), (a+d)

• 4

•(4-2) = 2

• (4+2) =6



I hope this will help you



-by ABHAY