Sum of 3 terms of AP is 3 and there product is -35.Find the AP
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sum of 3terms of ap is 3
let the numbers are
a+d,a,a-d
sum=3
a+d+a+a-d=3
a+a+a=3
3a=3
a=1
product=-35
a-d(a)[a+d]=-35
1-d[1][1+d]=-35
1-d(1+d)=-35
1-dsq=-35
35+1=dsq
36sqr=d
d=6
hope its help you
let the numbers are
a+d,a,a-d
sum=3
a+d+a+a-d=3
a+a+a=3
3a=3
a=1
product=-35
a-d(a)[a+d]=-35
1-d[1][1+d]=-35
1-d(1+d)=-35
1-dsq=-35
35+1=dsq
36sqr=d
d=6
hope its help you
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